With 4:47 remaining in their game vs Washington, the Baltimore Ravens 
scored a touchdown that increased their lead from 21-20 to 28-20.  You 
probably know what happened next: the Redskins drove down the field, 
overcoming the loss of RG3 along the way, with Kirk Cousins hitting 
Pierre Garcon for a touchdown with 32 seconds remaining and then 
successfully executing a QB draw for the tying two-point conversion; 
Washington then went on to win the game in overtime.  In the aftermath 
of the game, some analysts, such as Grantland's Bill Barnwell and espn.com's Gregg Easterbrook (aka TMQ) suggested that 
Baltimore ought to have attempted a two-point conversion after their 
touchdown, which if successful would have given them a nearly 
insurmountable nine-point lead.  They both suggest that the two-point 
try offered great upside with little risk, pointing out that even if it 
failed, Washington would still almost certainly only end up tying the 
game with a touchdown.
But closer examination of the issue reveals that this is a rare case 
where Barnwell and Easterbrook (normally very sharp football thinkers) 
are wrong, and the conventional wisdom manifested in John Harbaugh's 
decision is right.  In fact, Barnwell and Easterbrook have fallen prey 
to the very same error that underlies many of the legitimately foolish 
strands of football's conventional wisdom: defining the issue in terms 
of vaguely-specified risk/reward criteria, instead of a rigorous 
analysis of the win probabilities involved.  The math involved in this 
particular case is actually too simple to be of much inherent interest, 
but it still serves as a valuable reminder of how important it is to 
think through these questions in quantitative terms - we see that even 
top-caliber analysts can be led astray when they rely entirely on their 
intuition.  
Here, the key point is that by kicking an extra point, Baltimore made it
 considerably more difficult for Washington to tie the game with a 
touchdown, as they now needed to convert a two-point try, rather than 
simply kicking an extra point.  The fact that Washington would have 
faced a much easier road to a tied game following a failed two-point 
attempt by Baltimore may not trigger any visceral perception of risk, 
but it still endows the extra point with a fair amount of upside in 
relative to a failed two-point try.  In order to estimate the success 
probability at which Baltimore's two-point try would have been a 
break-even proposition, we need to weigh this upside against the greater
 reward offered by a successful two-point conversion, which would result
 in a nine-point lead.  
We will use P(B) to denote the probability of Baltimore successfully 
executing a two-point conversion, P(W) to refer to the probability of 
Washington executing a successful two-point conversion.  (For 
simplicity, we assume that probability of extra point success is 100% - 
this variable largely cancels out on both sides of the equation, and the
 logic of the conclusion can easily be restated in order to allow this 
assumption to be relaxed.)  Now, restricting ourselves to the space of 
potential outcomes where Washington outscores Baltimore by exactly one 
touchdown over the remainder of the game (since these are the only 
feasible outcomes where Baltimore's post-TD decision is directly 
reflected in the final result) we see that Baltimore faces the following
 dilemma:
Option 1: Kick an extra point.  Now with probability P(W), the game goes
 to overtime, and with probability 1-P(W) Baltimore wins in regulation.
Option 2: Attempt a two-point conversion.  Now with probability P(B), 
Baltimore wins the game in regulation, and with probability 1-P(B), the 
game goes to overtime.
So to first approximation, Baltimore's two-point try breaks even if P(B)
 = 1-P(W); i.e. if their probability of success is as high as 
Washington's probability of failure.  While we cannot say for certain 
that this hurdle was not reached in the game, we note that it requires 
that at least one team to have a two-point success probability of over 
50%* - in which case they ought to be adopting the two-point conversion 
as their general post-touchdown strategy.  This conclusion can be 
summarized by pointing out that statistically, a team is better off 
needing to defend a two-point conversion than they are needing to make 
one of their own, unless one or both teams would be successful more than
 half the time.  
And in fact, the two-point conversion attempt has yet another factor in 
its disfavor.  As indicated above, the game situations where Washington 
outscores Baltimore by exactly one touchdown over the remainder of the 
game are the only ones in which Baltimore's post-TD decision has direct 
bearing on the final score.  But the probability of the various 
rest-of-game outcomes is not an entirely exogenous factor to their 
decision; in particular, a successful two-point conversion, by 
clarifying Washington's scoring requirements for the remainder of the 
game, would make it slightly more likely that Washington would outscore 
them by one TD plus another score of some variety, thereby winning the 
game outright themselves.  This is still a very low-probability event - 
scoring twice in the final five minutes is always a tall order - but it 
still means that a slight downward adjustment to the equity of the 
two-point try is in order.  Therefore, even if the nominal break-even 
point of P(B) = 1-P(W) were reached, we conclude that the two-point 
attempt would still be an incorrect decision.  
* Here is we can bring extra-point probability back into the mix: the 
actual threshold is not 50%, but P(XP)/2.  But the general consideration
 remains the same: if a team's two-point probability were in excess of 
this value, they ought to attempt a two-point conversion after virtually
 every touchdown.
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